Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

According to the following reaction, how many grams of iron(II) chloride will be formed upon the complete reaction of 21.6 grams of hydrochloric acid with excess iron?
iron (s) + oxygen (g) Arrow.gifiron(II) oxide (s)

Sagot :

Eduard22sly

Answer:

37.58 g of FeCl₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe + 2HCl —> FeCl₂ + H₂

Next, we shall determine the mass of HCl that reacted and the mass of FeCl₂ produced from the balanced equation. This is can be obtained as follow:

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

Molar mass of FeCl₂ = 56 + (2×35.5)

= 56 + 71

= 127 g/mol

Mass of FeCl₂ from the balanced equation = 1 × 127 = 127 g

SUMMARY:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Finally, we shall determine the mass of FeCl₂ produced by the reaction of 21.6 g of HCl. This can be obtained as follow:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Therefore, 21.6 g of HCl will react to produce = (21.6 × 127)/73 = 37.58 g of FeCl₂.

Thus, 37.58 g of FeCl₂ were obtained from the reaction.

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.