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Each side of a square is increasing at a rate of 5 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 49 cm2

Sagot :

Answer:

25 cm^2/sec

Step-by-step explanation:

I my understanding of the question.  It doesn't matter what the area of the square is currently is, for example if the area is 25 cm^2, 36 cm^2 or 49cm^2, the rate will ALWAYS increase by rate squared.

      rate(a)  x  rate(b)  =  rate(area)           in this case rate(a) = rate(b)

        (5 cm^2/s) (5 cm^2/s)  = 25 cm^2/s

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