Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
a. df = 3, chi-square = 1.7333, p value = 7.815
b. we fail to reject null hypothesis
c. it is independent of kernel texture
Explanation:
h0; there is independence
h1; no independence
9:3:3:1 this is the phenotypic ratio
9+3+3+1 = 16
330 red smooth + 97 red wrinkled + 101 yellow smooth + 32 yellow wrinkled
total observed = 560
1. the degree of freedom = n-1
n =4, 4-1 = 3
to get the chi square computation
(O-E)²/E
expected value for red smooth,
9/16 x 560 = 315
chisquare = (330-315)²/315 = 0.7143
expected for red wrinkled
3/16*560 = 105
chisquare = (97-105)²/105 = 0.6095
expected for yellow smooth
3/16*560 = 105
chisquare = (101-105)²/105 = 0.1524
expected for yelow wrinkled
1/16 * 560 = 35
chisquare = (32-35)²/35 = 0.2571
total chisquare = 0.7143+0.6095+0.1524+0.2571
= 1.7333
with probability = 0.05, df = 3, the value of the chi square from x² table = 7.815
1.7333 < 7.815
so we fail to reject the null
c. we conclude that kernel color is independent of kernel texture
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.