Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒ [tex]a=\frac{2S}{t^2}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{2\times 13.0}{(5.20)^2}[/tex]
⇒ [tex]=\frac{26}{27.04}[/tex]
⇒ [tex]=0.961538 \ m/s^2[/tex]
(a)
The mass of the block will be:
⇒ [tex]m=\frac{F}{a}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{81.0}{0.961538}[/tex]
⇒ [tex]=84.240 \ kg[/tex]
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒ [tex]v=at[/tex]
On substituting the values, we get
⇒ [tex]=0.961538\times 5.00[/tex]
⇒ [tex]=4.8076 \ m/s[/tex]
In time, t = 5.00 s
The distance moved by the block will be:
⇒ [tex]d=vt[/tex]
On putting the values, we get
⇒ [tex]=4.8076\times 5.00[/tex]
⇒ [tex]=24.038 \ m[/tex]
