Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
See explanation
Explanation:
If i have a sodium halide salt which can be any of NaCl, NaBr, or NaI, addition of AgNO3 and ammonia leads to the formation of various colour of precipitate which helps to identify the particular halogen atom that is combined with sodium.
If the sodium halide is NaCl, a white precipitate is formed when AgNO3 is added. The precipitate is soluble in ammonia solution.
If the sodium halide is NaBr, a cream precipitate is formed when AgNO3 is added. This precipitate is sparingly soluble in excess ammonia solution.
If the sodium halide is NaI, a yellow precipitate is formed when AgNO3 is added. This precipitate is insoluble in excess ammonia solution
b) The true color of a halogen is only observed when it is viewed in hexane. iodine in hexane has a purple colour. Hence, the reaction that occured is;
NaI(aq) + Cl2 → NaCl(aq) + I2
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.