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Sagot :
Answer:
[tex]Mean = 47[/tex]
[tex]n = 6[/tex]
[tex]s= 16.56[/tex]
[tex]\sqrt n = 2.45[/tex]
[tex]SEM = 11.55[/tex]
Step-by-step explanation:
Given: The above data
Solving (a): Mean of each group
Mean is calculated as:
[tex]Mean = \frac{\sum x}{N}[/tex]
[tex]Mean = \frac{55 + 31 + 58 + 20 + 47 + 37+68 + 32 + 85 + 69 +58 + 52+26 + 47 + 30 +35 + 53 + 43}{18}[/tex]
[tex]Mean = \frac{846}{18}[/tex]
[tex]Mean = 47[/tex]
Solving (b): The sample size of each group
This is the number of rows in each group.
Hence:
[tex]n = 6[/tex]
Solving (c): Standard deviation (s)
This is calculated as:
[tex]s = \sqrt{\frac{\sum (x - \bar x)^2}{N}}[/tex]
So, we have:
[tex]s= \sqrt{\frac{(55 - 47)^2 + (31 - 47)^2 +......... + (43 - 47)^2}{18}}[/tex]
[tex]s= \sqrt{\frac{4936}{18}}[/tex]
[tex]s= \sqrt{274.22}[/tex]
[tex]s= 16.56[/tex]
Solving (d): Square root of n
[tex]\sqrt n = \sqrt 6[/tex]
[tex]\sqrt n = 2.45[/tex]
Solving (e): SEM
This is calculated as:
[tex]SEM = \frac{s}{\sqrt N}[/tex]
[tex]SEM = \frac{47}{\sqrt{16.56}}[/tex]
[tex]SEM = \frac{47}{4.07}[/tex]
[tex]SEM = 11.55[/tex]
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