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Find the equation of the straight line which passes through each of the following pairs of points.
(1,4) (3,10)


Sagot :

Answer:

y = 3x + 1

Step-by-step explanation:

First, find slope:

[tex]y2 - y1 / x2 - x1[/tex]

[tex]10 - 4/ 3 - 1 = 6 / 2 = 3[/tex]

Then, put the equation into point-slope form using the point (1, 4):

[tex]y - y1 = m(x - x1)[/tex]

where m is the slope

y - 4 = 3(x - 1)

If you want to put this into slope-intercept form, it would be

[tex]y-4=3(x-1)\\y - 4 = 3x - 3\\y = 3x + 1[/tex]