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If 42 grams of HCl reacts, what is the theoretical yield of hydrogen gas produced?

Sagot :

sebassandin

Answer:

[tex]m_{H_2}=1.2gH_2[/tex]

Explanation:

Hello!

In this case, since the metal is not given, we can set up the following chemical reactions:

[tex]Be+2HCl\rightarrow BeCl_2+H_2[/tex]

Thus, since the HCl is a 2:1 mole ratio with hydrogen, we can use the following setup to calculate the required mass of hydrogen:

[tex]m_{H_2}=42gHCl*\frac{1molHCl}{36.45gHCl}*\frac{1molH_2}{2molHCl} *\frac{2.02gH_2}{1molH_2} \\\\m_{H_2}=1.2gH_2[/tex]

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