Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
[tex]sin\ \varnothing = \frac{-1}{10}\sqrt 2[/tex]
[tex]cos\ \varnothing = \frac{-7}{10}\sqrt 2[/tex]
[tex]tan\ \varnothing = \frac{1}{7}[/tex]
[tex]cot\ \varnothing = 7[/tex]
[tex]sec\ \varnothing = \frac{-5}{7}\sqrt 2[/tex]
[tex]csc\ \varnothing = -5\sqrt 2[/tex]
Step-by-step explanation:
Given
[tex]N = (-7,-1)[/tex] --- terminal side of [tex]\varnothing[/tex]
Required
Determine the values of trigonometric functions of [tex]\varnothing[/tex].
For [tex]\varnothing[/tex], the trigonometry ratios are:
[tex]sin\ \varnothing = \frac{y}{r}[/tex] [tex]cos\ \varnothing = \frac{x}{r}[/tex] [tex]tan\ \varnothing = \frac{y}{x}[/tex]
[tex]cot\ \varnothing = \frac{x}{y}[/tex] [tex]sec\ \varnothing = \frac{r}{x}[/tex] [tex]csc\ \varnothing = \frac{r}{y}[/tex]
Where:
[tex]r^2 = x^2 + y^2[/tex]
[tex]r = \sqrt{x^2 + y^2[/tex]
In [tex]N = (-7,-1)[/tex]
[tex]x = -7[/tex] and [tex]y = -1[/tex]
So:
[tex]r = \sqrt{(-7)^2 + (-1)^2[/tex]
[tex]r = \sqrt{50[/tex]
[tex]r = \sqrt{25 * 2[/tex]
[tex]r = \sqrt{25} * \sqrt 2[/tex]
[tex]r = 5 * \sqrt 2[/tex]
[tex]r = 5 \sqrt 2[/tex]
Solving the trigonometry functions
[tex]sin\ \varnothing = \frac{y}{r}[/tex]
[tex]sin\ \varnothing = \frac{-1}{5\sqrt 2}[/tex]
Rationalize:
[tex]sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}[/tex]
[tex]sin\ \varnothing = \frac{-\sqrt 2}{5*2}[/tex]
[tex]sin\ \varnothing = \frac{-\sqrt 2}{10}[/tex]
[tex]sin\ \varnothing = \frac{-1}{10}\sqrt 2[/tex]
[tex]cos\ \varnothing = \frac{x}{r}[/tex]
[tex]cos\ \varnothing = \frac{-7}{5\sqrt 2}[/tex]
Rationalize
[tex]cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}[/tex]
[tex]cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}[/tex]
[tex]cos\ \varnothing = \frac{-7\sqrt 2}{10}[/tex]
[tex]cos\ \varnothing = \frac{-7}{10}\sqrt 2[/tex]
[tex]tan\ \varnothing = \frac{y}{x}[/tex]
[tex]tan\ \varnothing = \frac{-1}{-7}[/tex]
[tex]tan\ \varnothing = \frac{1}{7}[/tex]
[tex]cot\ \varnothing = \frac{x}{y}[/tex]
[tex]cot\ \varnothing = \frac{-7}{-1}[/tex]
[tex]cot\ \varnothing = 7[/tex]
[tex]sec\ \varnothing = \frac{r}{x}[/tex]
[tex]sec\ \varnothing = \frac{5\sqrt 2}{-7}[/tex]
[tex]sec\ \varnothing = \frac{-5}{7}\sqrt 2[/tex]
[tex]csc\ \varnothing = \frac{r}{y}[/tex]
[tex]csc\ \varnothing = \frac{5\sqrt 2}{-1}[/tex]
[tex]csc\ \varnothing = -5\sqrt 2[/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.