Answered

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Assume we have two lists, list A and list B. List A contains the numbers [20,10,20], while list B contains the numbers [40,10,30,20,40,30]. We choose one number from list A randomly and one number from list B randomly. What is the chance that the number we drew from list A is larger than or equal to the number we drew from list B

Sagot :

fichoh

Answer:

5/ 18

Explanation:

Given :

List A: [20,10,20]

List B: [40,10,30,20,40,30]

Chance that number drawn from list A is larger than or equal to that drawn dlfrom list B.

If:

A = 20

B ≤ 20 : [10,20] = 2

A = 10

B ≤ 10 : [10] = 1

A = 20

B ≤ 20 : [10,20] = 2

Probability = Required outcome / Total possible outcomes

Hence,

required outcome = (2 + 2 +1) = 5

Total possible outcomes = 3C1 * 6C1 = (3 * 6) = 18

Hence,

chance that the number we drew from list A is larger than or equal to the number we drew from list B

= 5 / 18

lhmarianateixeira

In this exercise we have to use the knowledge in computational language in python to describe a code that best suits, so we have:

The code can be found in the attached image.

To make it simpler we can write this code as:

import random

A=[20,10,20]

B=[40,10,30,20,40,30]

print(random.choice(A))

print(random.choice(B))

See more about python at brainly.com/question/19705654

View image lhmarianateixeira
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