Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

How many grams are 3.01 x 10^23 molecules of methane

Sagot :

wrestlingedgar21

One mole of any gas at STP takes up 22.4 L of volume.

one mole of gas = 22.4 L ..... (a)

one mole of gas has 6.02 x

10

23

particles( Molecules) ..... (b)

equating (a) and (b) we get

6.022 x

10

23

particles (Molecules) = 22.4 L

Making conversion factors 22.4 L / 6.02 x

10

23

particles or

6.02 x

10

23

particles / 22.4 L

since we want change the # of molecules into L we will use the conversion factor that when multiplied by the given number

gives L as the final unit.

3.01 x

10

23

particles x 22.4 L / 6.02 x

10

23

particles

11.2 L

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.