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What volume, in milliliters, of a 0.140 M solution of KCl contains 2.65 g of the compound?
Express the volume to three significant figures and include the appropriate units.

Sagot :

s5255256

Answer:

Calculate moles KCl: 2.55 g / 74.55 g/mol = 0.0342 moles KCl

Volume KCl = 0.0342 mol X (1 L/0.150 mol) = 0.228 L X 1000 mL/L = 228 mL

Explanation:

Volume=288mL

Given:

Molarity=0.140 M

Mass=2.65 g

To find:

Volume=?

Molar mass of KCl = 74.55 g/mol

Firstly, we need to calculate the number of moles of KCl:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} \\\\\text{Number of moles}=\frac{2.65g}{74.55g/mol} \\\\\text{Number of moles}=0.0355 moles[/tex]

In order to calculate the volume,

[tex]\text{ Volume of KCl} = 0.0342 mol * (1 L/0.150 mol) \\\\\text{ Volume of KCl} = 0.228 L * 1000 mL/L \\\\\text{ Volume of KCl} = 228 mL[/tex]

The volume in mL will be 228mL.

Learn more:

brainly.com/question/15356425

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