Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

How many grams of ammonium sulfate are needed to make a 0.25 M
solution at a concentration of 6 M?

Sagot :

emilyluvsya
198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

The amount in grams of ammonium sulfate are needed to make a 0.25L solution at a concentration of 6 M is 198 grams.

How do we calculate grams from moles?

Mass (W) in grams from moles (n) of any substance will be calculated by using the below equation as:

n = W/M, where

M = molar mass

And for this question moles will be calculated by using the below formula:

M = n/V, where

M = molarity of the solution = 6M

V = volume of the solution = 0.25 L

On putting values on the above equation, we get

n = (6)(0.25) = 1.5 moles

Now mass of 1.5 moles of ammonium sulfate will be calculated by using the first formula as:

W = (1.5mol)(132g/mol) = 198g

Hence required mass of ammonium sulfate is 198 grams.

To know more about mass & moles, visit the below link:
https://brainly.com/question/1358482

#SPJ2

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.