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Today’s cafeteria specials are a turkey sandwich and a pepperoni pizza. During 1st lunch, the cafeteria sold 70 turkey sandwiches and 29 pepperoni pizzas for a total of $367. During 2nd lunch, 70 turkey sandwiches and 45 pepperoni pizzas were sold for a total of $415. How much does each item cost?

Sagot :

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Answer:

$4 and $3

Step-by-step explanation:

First, write out the equations as 70x + 29y = 367 and 70x + 45y = 415. Solve by using the elimination method by subtracting 70x from 70x. 45y minus 29y is equal to 16y. 415 minus 367 is 48. Divide 48 by 16, to get y is equal to get y is equal to three. Y represents pepperoni pizzas, so a pepperoni pizza costs $3. Plug a 3 into any equation for y and solve for x. 29 times 3 is 87. 367 minus 87 is 280. 280 divided by 70 is equal to 4, so x is equal to 4.

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The cost of each turkey is $4 while the cost of each pepperoni pizza is $3

Let x represent the cost of each turkey and let y represent the cost of each pepperoni pizza.

During 1st lunch, the cafeteria sold 70 turkey sandwiches and 29 pepperoni pizzas for a total of $367, this can be represented by the equation:

70x + 29y = 367    (1)

During 2nd lunch, 70 turkey sandwiches and 45 pepperoni pizzas were sold for a total of $415. this can be represented by the equation:

70x + 45y = 415     (2)

Solving equation (1) and (2) simultaneously gives:

x = 4, y = 3

Therefore the cost of each turkey is $4 while the cost of each pepperoni pizza is $3

Find out more at: https://brainly.com/question/16763389

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