Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
the force B is less than the maximum force consequently Boat B floats
Explanation:
To solve this exercise let's use the pressure defined
P = [tex]\frac{F}{A}[/tex]
F = P A
let's start for boat A
let's search the area
A = l a
A₁ = 45 126
A₁ = 5670 m²
the force applied by this ship is
F₁ = 2300 5670
F₁ = 1.3 10⁷ N
now we do the calculation for ship B
A₂ = 6 115
A₂ = 690 m²
F₂ = P₂ A₂
F₂ = 2700 690
F₂ = 1.8 10⁶ N
indicate that the force should not be greater than F₀ = 2.0 10⁶ N, let's look for the relationship with each one
[tex]\frac{F_1}{F_0}[/tex] = 1.3 10⁷/2 10⁶
F₁ = 6.5 F₀
This force is greater than the one that can resist therefore the ship and sinks
[tex]\frac{F_2}{F_o}[/tex] = 1.8 /2
F₂ = 0.9 F₀
therefore this force is less than the maximum force consequently Boat B floats
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
