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20 Points Answer This Pls Brainliest And Extra Points To Whoevers Right class=

Sagot :

Hrishii

Answer:

[tex] m\angle AED=90\degree [/tex]

[tex] m\angle DAE=53\degree [/tex]

[tex] m\angle BCE= 53\degree [/tex]

Step-by-step explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

[tex] \therefore m\angle AED=90\degree [/tex]

[tex] In\: \triangle AED[/tex]

[tex] m\angle DAE=90\degree-m\angle EDA [/tex]

[tex] m\angle DAE=90\degree-37\degree [/tex]

[tex] m\angle DAE=53\degree [/tex]

[tex] \because m\angle BCE= m\angle DAE [/tex]

(Alternate angles)

[tex] \therefore m\angle BCE= 53\degree [/tex]

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