At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
D
Step-by-step explanation:
Given a quadratic function in standard form
f(x) = ax² + bx + c ( a ≠ 0 )
• If a > 0 then minimum value
• If a < 0 then minimum value
For
f(x) = x² + 16x + 3
a = 1 > 0 then f(x) has a minimum value
The minimum is the value of the y- coordinate of the vertex.
The x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
Here a = 1 and b = 16 , then
[tex]x_{vertex}[/tex] = - [tex]\frac{16}{2}[/tex] = - 8
To find the y- coordinate of the vertex, substitute x = - 8 into f(x)
f(- 8) = (- 8)² + 16(- 8) + 3 = 64 - 128 + 3 = - 61
Thus the function has a minimum value of - 61 → D
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.