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Which shows the equation below written in the form ax^2+bx+c=0. x+9=4(x-1)^2

Sagot :

Answer:

[tex]4x^2 - 9x - 5 = 0[/tex]

Step-by-step explanation:

To place the equation in standard form, we expand the operations. So

[tex]4(x-1)^2 = x + 9[/tex]

[tex]4(x^2-2x+1) = x + 9[/tex]

[tex]4x^2 - 8x + 4 - x - 9 = 0[/tex]

Combining the like terms:

[tex]4x^2 - 9x - 5 = 0[/tex]