Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
You can answer this by using Pythagoras theorem. Okay, let me draw this first.
2 miles
V
________________________
| |
| |
| | << 1.5 miles
|_______________________|
^ Assume this is the rectangle. The long side is 2 miles while the shorter side is 1.5 miles.
So, to get the shortest distance, let's cut out a triangle from the rectangle.
/|
/ |
/ |
What we want to find is this one > / | << 2 miles
/ |
/______|
^ 1.5 miles (I know the size is not logical,but imagine it please)
So to get the diagonal length = [tex] \sqrt{{a^{2} }+ b^{2}} [/tex]
= [tex] \sqrt{{2^{2} }+ 1.5^{2}} [/tex]
= 2.5 miles
To calculate how much shorter = ( 2 miles + 1.5 miles) - 2.5 miles
= 3.5 miles - 2.5 miles
= 1.0 miles
Hope this help !
2 miles
V
________________________
| |
| |
| | << 1.5 miles
|_______________________|
^ Assume this is the rectangle. The long side is 2 miles while the shorter side is 1.5 miles.
So, to get the shortest distance, let's cut out a triangle from the rectangle.
/|
/ |
/ |
What we want to find is this one > / | << 2 miles
/ |
/______|
^ 1.5 miles (I know the size is not logical,but imagine it please)
So to get the diagonal length = [tex] \sqrt{{a^{2} }+ b^{2}} [/tex]
= [tex] \sqrt{{2^{2} }+ 1.5^{2}} [/tex]
= 2.5 miles
To calculate how much shorter = ( 2 miles + 1.5 miles) - 2.5 miles
= 3.5 miles - 2.5 miles
= 1.0 miles
Hope this help !
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
