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Sagot :
In order to accurately answer any fraction, it is best to have a common denominator (bottom of the fraction)
Since in [tex] \frac{45}{100} [/tex], 100 is the denominator, you need to make the other fraction with the same denominator
So Multiply [tex] \frac{6}{10} [/tex] by [tex] \frac{10}{10} [/tex]
[tex] \frac{6}{10} * \frac{10}{10} = \frac{60}{100} [/tex]
So [tex] \frac{45}{100} < \frac{60}{100} [/tex] or [tex] \frac{45}{100} < \frac{6}{10} [/tex]
You can do this another way which involves the opposite way of multiplying which is by dividing
Since you have to get a common denominator to measure accurately no matter what, you can divide
One thing to know is that when dividing fractions, both the denominator and numerator have to be divided by a factor to be divided and result in a whole number
[tex] \frac{45}{100} [/tex]÷[tex] \frac{5}{5} [/tex] = [tex] \frac{9}{20} [/tex]
So just have to multiple [tex] \frac{6}{10} by \frac{2}{2} [/tex]
[tex] \frac{6}{10} * \frac{2}{2} = \frac{12}{20} [/tex]
[tex] \frac{9}{20} < \frac{12}{20} [/tex]
[tex] \frac{9}{20} [/tex]⇒[tex] \frac{45}{100} [/tex]
[tex] \frac{12}{20} [/tex]⇒[tex] \frac{6}{10} [/tex]
The results are the same [tex] \frac{45}{100} < \frac{6}{10} [/tex]
Again [tex] \frac{6}{10} [/tex] is greater than [tex] \frac{45}{100} [/tex]
Since in [tex] \frac{45}{100} [/tex], 100 is the denominator, you need to make the other fraction with the same denominator
So Multiply [tex] \frac{6}{10} [/tex] by [tex] \frac{10}{10} [/tex]
[tex] \frac{6}{10} * \frac{10}{10} = \frac{60}{100} [/tex]
So [tex] \frac{45}{100} < \frac{60}{100} [/tex] or [tex] \frac{45}{100} < \frac{6}{10} [/tex]
You can do this another way which involves the opposite way of multiplying which is by dividing
Since you have to get a common denominator to measure accurately no matter what, you can divide
One thing to know is that when dividing fractions, both the denominator and numerator have to be divided by a factor to be divided and result in a whole number
[tex] \frac{45}{100} [/tex]÷[tex] \frac{5}{5} [/tex] = [tex] \frac{9}{20} [/tex]
So just have to multiple [tex] \frac{6}{10} by \frac{2}{2} [/tex]
[tex] \frac{6}{10} * \frac{2}{2} = \frac{12}{20} [/tex]
[tex] \frac{9}{20} < \frac{12}{20} [/tex]
[tex] \frac{9}{20} [/tex]⇒[tex] \frac{45}{100} [/tex]
[tex] \frac{12}{20} [/tex]⇒[tex] \frac{6}{10} [/tex]
The results are the same [tex] \frac{45}{100} < \frac{6}{10} [/tex]
Again [tex] \frac{6}{10} [/tex] is greater than [tex] \frac{45}{100} [/tex]
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