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solve 4(2a-1) = -10(a-5)

Sagot :

HolmesNWatson
Firstly, you've got to expand the brackets, this becomes;
8a-4= -10a+ 50
You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
Therefor, a=3
Hope this helps :)
VzDeath
[tex]8a-4=-10a+50[/tex]
[tex]+10a +10a \\ 18a-4=50 \\ +4 +4 \\ 18a=54 \\ /18 /18 \\ a=3[/tex]

Hope this helps :)

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