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the area of a rectangular invitation card is 3/10 square foot. Given that the length of the card is 4/5 foot find its perimeter

Sagot :

f=Foot

A=Area of the rectangular invitation card

L=Length of the rectangular invitation card

P=Perimeter

W=Width of the rectangular invitation card

------------------------

A=3/10f²

L=4/5f

-------------------------

A=L*W=3/10f²

So...

4/5f*W=3/10f²

So...

W=(3/10f²)/(4/5f)

So...

W=3/8f

--------------------------

Now:

P=2W+2L

=2(3/8f)+2(4/5f)

=3/4f+8/5f

=15/20f+32/20f

=47/20f

=(40/20+7/20)f

=(2+7/20)f

=2.35f
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