Answered

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The pressure in a tire is 101 kPa at 10.0°C, what will be the pressure of a tire at 45.0°C?

Sagot :

Answer:

P₂ = 113.49 kPa

Explanation:

Given that,

Initial pressure, P₁ = 101 kPa

Initial temperature, T₁ = 10.0°C = 283 K

Final temperature, T₂ = 45°C = 318 K

The relation between pressure and temperature is given by :

[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

Where

P₂ is the new pressure

So,

[tex]P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{101 \times 318}{283 }\\\\P_2=113.49\ kPa[/tex]

So, the new pressure is equal to 113.49 kPa.

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