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What is the pressure exerted by 2.5 mol of gas with a temperature of 25 Celsius and a volume of 12.2 L

Sagot :

maacastrobr

Answer:

5.01 atm

Explanation:

To answer this question, we're going to use the PV=nRT equation, where in this case:

  • P = ?
  • V = 12.2 L
  • n = 2.5 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

We input the data:

  • P * 12.2 L = 2.5 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

And finally solve for P:

  • P = 5.01 atm
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