Answer:
13/3
OR
4.33333
Step-by-step explanation:
For this function to be continuous, the second function must have the value of the limit as x approaches 3 of the first function.
To find [tex]\lim_{x \to 3} \frac{2x^2-3-15}{x-3}[/tex] we have to factor the top of the fraction
2x^2 - 3 -15
2x^2 - 18
2* (x^2 - 9)
2 * (x + 3) (x - 3)
this is perfect because this cancels out the x - 3 on the bottom
so the function become f(x) = 2 * (x + 3)
When 3 is plugged in it becomes 2 * (3 + 3) = 2 * 6 = 12
Now if you plug in 3 to the second function and make it equal to 12, you can find the value of k.
k*(3) - 1 = 12
k*3 = 13
k = 13/3
k = 4.33
