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Consider △XYZ Triangle X Y Z is shown. Angle X Z Y is a right angle. What are the ratios of sine, cosine, and tangent for angle Y? sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFraction Y Z Over X Z EndFraction; tan(Y) = StartFraction Y Z Over X Y EndFraction sin(Y) = StartFraction X Y Over X Z EndFraction; cos(Y) = StartFraction X Z Over X Y EndFraction; tan(Y) = StartFraction Y Z Over X Z EndFraction sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFraction Y Z Over X Y EndFraction; tan(Y) = StartFraction X Z Over Y Z EndFraction sin(Y) = StartFraction Y Z Over X Y EndFraction; cos(Y) = StartFraction X Z Over X Y EndFraction; tan(Y) = StartFraction X Z Over Y Z EndFraction

Sagot :

MrRoyal

Answer:

[tex]\sin Y= \frac{XZ}{XY}[/tex]

[tex]\cos Y= \frac{YZ}{XY}[/tex]

[tex]\tan Y= \frac{XZ}{YZ}[/tex]

Step-by-step explanation:

Given

See attachment for triangle

Required

Find [tex]\sin, \cos[/tex] and [tex]\tan[/tex] of angle Y

For angle Y:

[tex]Opposite = XZ[/tex]

[tex]Adjacent = YZ[/tex]

[tex]Hypotenuse = XY[/tex]

The [tex]\sin[/tex] of an angle is calculated as:

[tex]\sin\theta = \frac{Opposite}{Hypotenuse}[/tex]

So:

[tex]\sin Y= \frac{XZ}{XY}[/tex]

The [tex]\cos[/tex] of an angle is calculated as:

[tex]\cos\theta = \frac{Adjacent}{Hypotenuse}[/tex]

So:

[tex]\cos Y= \frac{YZ}{XY}[/tex]

The [tex]\tan[/tex] of an angle is calculated as:

[tex]\tan\theta = \frac{Opposite}{Adjacent}[/tex]

So:

[tex]\tan Y= \frac{XZ}{YZ}[/tex]

View image MrRoyal

Answer:

C, short answer

Step-by-step explanation:

trust

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