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Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it completely and throws Sheila forward onto the pavement. If there is no net force on the system, what is Sheila's velocity immediately after she is thrown from the bike? 1.8 m/s 2.0 m/s 5.0 m/s 5.7 m/s

Sagot :

hamzaahmeds

Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

[tex]Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\[/tex]

where,

Total Initial Momentum = 340 kg.m/s

m₁ = mass of bike

v₁ = final speed of bike = 0 m/s

m₂ = mass of Sheila = 60 kg

v₂ = final speed of Sheila = ?

Therefore,

[tex]340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\[/tex]

v₂ = 5.7 m/s

pdossanto0001

Answer:

5.7 I got it right on edg 2021

Explanation:

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