Answered

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A small 10.0 g ball is held to a slingshot
that is stretched 6.0 cm. The spring
constant is 2.0 × 102 N/m.
a. What is the elastic potential energy
of the slingshot before it is
released?

Sagot :

OverpoweredNoob

Answer:

0.36 J

Explanation:

[tex]PE = \frac{1}{2} kx^{2} \\PE = \frac{1}{2} (200 N/m)(0.06 m)^{2} \\PE = 0.36 J[/tex]

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