Answered

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Having a Hitchhiker’s Thumb (T) is dominant over not having Hitchhiker’s Thumb (t). If a person that is Tt has children with a person that is Tt, what is the probability of their children that will not have a Hitchhiker’s Thumb?

a
0%
b
25%
c
50%
d
75%

Sagot :

15919

Answer:

B. 25%

Explanation: If you draw a Punnett square you see that you get TT, Tt, Tt, and tt. Now if T (Hitchhikers thumb) is dominant over t (non hitchhikers thumb) TT, Tt, and Tt are all going to have hitchhikers thumb and only tt won't have hitchhikers thumb. 1 out of 4 is equal to 25%.
The answer is B. 25%
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