piperowynn
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Graph y ≤ (x + 2)^2.

Click on the graph until the correct graph appears.

Graph Y X 22 Click On The Graph Until The Correct Graph Appears class=
Graph Y X 22 Click On The Graph Until The Correct Graph Appears class=
Graph Y X 22 Click On The Graph Until The Correct Graph Appears class=
Graph Y X 22 Click On The Graph Until The Correct Graph Appears class=

Sagot :

awalters2023

Answer:

the first one is the correct one

Step-by-step explanation:

a great way to check this is to use demos .com

Iilyevans

Answer:

its the first one

Step-by-step explanation:

our  vertex is (-2,0)

so replace it in the equation y ≤ (x + 2)^2

so, 0 ≤ (-2 + 2)^2

= 0 ≤ (-4)^2

= 0 ≤ 16

look at that statement, is 0 less than or equal to 16? Yes. Therefore it is correct, so you shade out side of the parabola.

TIP: If the parabola opens up and:

        y <, then shade outside.

        y >, then shade inside.

Do the opposite if the parabola opens down.

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.