NHANS014473
Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A rifle can shoot a 4.2 g bullet at a speed of 965 m/s. If the work on the bullet is done over a distance of 0.75 m, what is the average force on the bullet?

Sagot :

Cricetus

Answer:

The average force on the bullet will be "2607.43 N".

Explanation:

The given values are:

Mass of the bullet,

m = 4.2 g

Final speed,

v = 965 m/s

Initial speed,

u = 0

Distance,

S = 0.75 m

According to the Energy theorem,

⇒  [tex]Work \ done = Change \ in \ kinetic \ energy[/tex]

⇒  [tex]F S = (\frac{1}{2} )m(v^2 - u^2)[/tex]

On substituting the values, we get

⇒  [tex]F\times 0.75=0.5\times 0.0042 [(965)^2 - 0][/tex]

⇒  [tex]0.75 F = 0.5\times 0.0042\times 931225[/tex]

⇒  [tex]0.75F=1955.57[/tex]

⇒        [tex]F=\frac{1955.57}{0.75}[/tex]

⇒            [tex]=2607.43 \ N[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.