NHANS014473
Answered

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A rifle can shoot a 4.2 g bullet at a speed of 965 m/s. If the work on the bullet is done over a distance of 0.75 m, what is the average force on the bullet?

Sagot :

Cricetus

Answer:

The average force on the bullet will be "2607.43 N".

Explanation:

The given values are:

Mass of the bullet,

m = 4.2 g

Final speed,

v = 965 m/s

Initial speed,

u = 0

Distance,

S = 0.75 m

According to the Energy theorem,

⇒  [tex]Work \ done = Change \ in \ kinetic \ energy[/tex]

⇒  [tex]F S = (\frac{1}{2} )m(v^2 - u^2)[/tex]

On substituting the values, we get

⇒  [tex]F\times 0.75=0.5\times 0.0042 [(965)^2 - 0][/tex]

⇒  [tex]0.75 F = 0.5\times 0.0042\times 931225[/tex]

⇒  [tex]0.75F=1955.57[/tex]

⇒        [tex]F=\frac{1955.57}{0.75}[/tex]

⇒            [tex]=2607.43 \ N[/tex]

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