Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
ρ = 20.4 kg / m³
Explanation:
For this exercise we use Archimedes' principle, the thrust on a submerged body is equal to the weight of the released liquid
B = ρ g V_liquid (1)
let's write the equilibrium equation
F -W + B = 0
B = W -F
let's calculate
B = 0.900 9.8 - 2.94
B = 5.88 N
From equation 1
V_{liquid} = [tex]\frac{B}{\rho_{Hg} g}[/tex]
V_{liquid} = [tex]\frac{5.88}{13.6 \ 10^3 \ 9.8}[/tex]
V_{liquid} = 4.41176 10⁻⁵ m³
in this case it is indicated that the body is completely submerged
V_body = V_liquid = V
the definition of density is
ρ = m / V
ρ = [tex]\frac{0.900 \ 10^{-3}}{ 4.41176 \ 10^{-5} }[/tex]
ρ = 2.04 10¹ kg / m³
ρ = 20.4 kg / m³
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
