sandovalmelanie05
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A 1,500 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 sec. What is the acceleration of the car?

Sagot :

abhi569

Answer:

3.375 m/s²

Explanation:

Using equation of motion:

v = u + at

Here, v = 27m/s & u = 0m/s & t = 8 sec

Let the acceleration be a.

=> 27 = 0 + 8(a)

=> 27/8 = a

=> 3.375 m/s²

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.