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What relation does not have an initial value of 50
A y=50
B y=50+8x
C y =50x
D y=50-x


Sagot :

i guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50