Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

ANYONE KNOW HOW TO SOLVE THIS!!!! PLEASE HELP ME!!! IT IS SOLVING SYSTEM EQUATIONS BY SUBSTITUTING!!
x+8y=20
4x-y=14


Sagot :

Answer:

x=4

y=2

Step-by-step explanation:

x+8y=20

4x−y=14

​To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

x+8y=20,4x−y=14

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

x+8y=20

Subtract 8y from both sides of the equation.

x=−8y+20

Substitute −8y+20 for x in the other equation, 4x−y=14.

4(−8y+20)−y=14

Multiply 4 times −8y+20.

−32y+80−y=14

Add −32y to −y.

−33y+80=14

Subtract 80 from both sides of the equation.

−33y=−66

Divide both sides by −33.

y=2

Substitute 2 for y in x=−8y+20. Because the resulting equation contains only one variable, you can solve for x directly.

x=−8×2+20

Multiply −8 times 2.

x=−16+20

Add 20 to −16.

x=4

The system is now solved.

x=4,y=2