Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A surveyor leaves her base camp and drives 43km on a bearing of 032°.She then drives 28km on a bearing of 154°.How far is she then from her base camp and what is her bearing from it

Sagot :

fichoh

Answer:

36.84km ; 252.13°

Step-by-step explanation:

Using the cosine rule :

a² = b² + c² - 2bcCosA

a² = 28² + 43² - (2*28*43)*Cos58

a² = 2633 - 1276.0455

a² = 1356.9544

a = sqrt(1356.9544)

a = 36.8368

a = 36.84 km

For the bearing,

Obtain the angle at B using the Sine rule

a/SinA = b/SinB

36.84/sin58 = 28/sinB

36.84*SinB = 28 * Sin58

SinB = 23.745346 / 36.84

SinB = 0.6445533

B = sin^-1(0.6445533)

B = 40.13°

180 + (32 + 40.13)

180 - 72.13

= 252.13°

View image fichoh
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.