Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
(x + 1)² + (y + 1)² = (√6)²
Step-by-step explanation:
Group the x- and y- terms together:
9x^2 + 18x + 9y^2 + 9y = 36
Factor out the coefficient 9:
x^2 + 2x + y^2 + y = 4
Complete the square of x^2 + 2x and then do the same for y^2 + 2y:
x^2 + 2x + 1 - 1 + y^2 + 2y + 1 - 1 = 4
Rewrite x^2 + 2x + 1 as the square of the binomial x + 1:
(x + 1)^2 + (y + 1)^2 - 2 = 4
Collect the constant terms on the right side:
(x + 1)^2 + (y + 1)^2 = 6
Rewrite 6 as (√6)^2:
(x + 1)² + (y + 1)² = (√6)² is the equation in standard form (x - h)² + (y - k)² = r²
Completing the square is done as follows: x^2 + 2x
Start with x^2 + 2x
1. Take half of the coefficient of x, which results in 2/2, or 1
2. Square this result and add it to, and subtract it from x^2 + 2x
x^2 + 2x + 1 - 1
3. Rewrite the first three terms as the square of a binomial:
x^2 + 2x + 1 - 1 = (x + 1)² - 1.
Do the same for y² + 2y.
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.