Answered

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How much heat is required for 25.0g of water to rise in temperature from 35.0 to 75.0°C?

Formulas~
*q = mcT (temp change)
*q = mH (phase change)

Sagot :

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

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