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Sagot :
Answer:
The frequency of the non-taster phenotype among people of European descent is 49% or 0.49
Explanation:
Let us assume that the allele for tasting PTC is T, while that for not tasting PTC is t.
According to the Hardy-Weinberg equation : p² + 2pq + q² = 1
Also p + q = 1
Where p² is the frequency of individuals with the TT genotype for tasting PTC,; wow is the frequency of individuals with the heterozygous allele for tasting PTC, while q² is the frequency of the individuals with tt genotype expressed as the non-taster phenotype since the allele for tasting is dominant over that of the non-taster.
From the information provided 51% of people of European descent are tasters. Also, tasting PTC is dominant over non-tasting. This implies that individuals with TT genotype and Tt genotype will be phenotypically expressed as tasters.
Therefore p² + 2pq = 51% or 0.51
q² = 1 - p² + 2pq
q² = 1 - 0.51
q² = 0.49 or 49%
The frequency of the non-taster phenotype among people of European descent is 49% or 0.49
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