Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".
Explanation:
Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.
Let's look at the speed of the car
[tex]F = m a\\\\a =\frac{F}{m}[/tex]
We use movies and find lips
[tex]\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t[/tex]
The moment is defined by
[tex]\to p = m v[/tex]
The moment change
[tex]\Delta p = m v - m v_0[/tex]
Let's replace the speeds in this equation
[tex]\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0 + F t - m v_0\\\\\Delta p = F t[/tex]
They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
