Explanation:
So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......
[tex] \frac{v1}{t1} = \frac{v2}{t2} [/tex]
temperature is measured in degrees Kelvin.
And
[tex] v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?[/tex]
?mL
0.403 L is the new volume where the initial volume is 275 mL and the initial temperature is 273 K.
Gas laws relate to the pressure, volume, and temperature of a gas. Boyle's law—named for Robert Boyle—states that, at constant temperature, the pressure P of a gas varies inversely with its volume V, or PV = k, where k is a constant.
The relationship between volume and temperature is: [tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex] where [tex]V_1[/tex]and [tex]T_1[/tex] are the initial volumes and [tex]V_2[/tex] and [tex]T_2[/tex] are the final volumes.
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
Given data:
[tex]V_1 =[/tex] 275 mL, [tex]T_1 =[/tex] 0
[tex]V_2 =[/tex] 275 mL, [tex]T_2 =[/tex] 130
Putting all the values in the equation:
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
[tex]\frac{0.275}{273} =\frac{V_2}{403}[/tex]
[tex]V_2 =[/tex] 0.403 L
Hence, 0.403 L is the new volume.
Learn more about gas law here:
https://brainly.com/question/12669509
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