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Sagot :
Answer: The molarity of diluted solution is 0.00031 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]Pb(NO_3)_2[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.1042g}{331.2g/mol}=0.00031mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.00031mol\times 1000}{100ml}=0.0031M[/tex]
According to the dilution law,
[tex](stock)M_1V_1=M_2V_2(dilute)[/tex]
Putting in the values we get:
[tex]0.0031\times 5.00=M_2\times 50.00[/tex]
[tex]M_2=0.00031M[/tex]
Therefore, the molarity of diluted solution is 0.00031 M
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