Georgescratch
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What is the volume of 2.3 mol Cl2 at 290 K and 0.89 atm?



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Sagot :

Raineyvonahnen

Answer:

62 L

Explanation:

We are given that:

n = 2.3 mol

R = 0.082 L*atm/(mol*K), the ideal gas constant in the required units

T = 290 K

P = 0.89 atm.

therefor:

V = nRT/P

= [(2.3 mol)(0.082 L*atm)(290 K)/(mol*K)]/(0.89 atm)

= 62 L

The volume of 2.3 mol CL2 will be 62 L.

What is volume?

A three-dimensional element's area of coverage. The measurement of volume is done in cubic units. Decibels are a unit of measurement for the volume of sound.

Calculation of volume.

Volume can be determined by using the formula.

PV = nRT

where, P = pressure, V = volume, n = number of moles, R = gas constant and T = temperature,

It is given that, n = 2.3 mol, T = 290 K and P = 0.89 atm.

Put the value of given data in volume equation,

V = n RT/ P

V = 2.3 mol × 0.082 × 290 /0.89

V = 62 L.

Therefore, the volume will be 62 L.

To know more about volume.

https://brainly.com/question/13338592

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