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Sagot :
Answer:
Pooled Standard Error =0.7157
Step-by-step explanation:
The missing data is
Mean n Std. Deviation Std. Error
group1 6.89 9 1.269 0.423
group2 5.33 9 1.732 0.577
Standard Error= Std. Deviation / √n
First we calculate pooled standard deviation from the pooled variance formula
Sp²= (n1 – 1)* (s1)² + (n2 – 1) *(s2)²/(n1 + n2 – 2)
= 8*(1.269)² + 8 (1.732)²/ ( 9+9-2)
= 12.882888 + 23.998592/16
=2.3050925
Sp = √ 2.3050925 =1.51825
Pooled Standard Error = Sp *sqrt(1/n1 + 1/n2)
=1.51825 *(0.4714)
=0.7157
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