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Sagot :
Explanation:
From Faraday's law,
[tex]e m f &=-\frac{d \phi}{d t} \\ &=-\frac{d}{d t}(B A \cos \theta) \\ &=-\frac{d}{d t}(B l h \cos \theta) \\ &=-B l \cos \theta \frac{d h}{d t} \\ &=-B l v \cos 0^{\circ} \\ &=-B l v[/tex]
Here, B is the magnetic field, l is the length of the rod, and v is the velocity of the rod.
[tex]e m f &=-B l(\sqrt{2 g h}) \\ 9.2 \times 10^{-4} \mathrm{~V} &=-B(0.90 \mathrm{~m})\left(\sqrt{2\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)(32 \mathrm{~m})}\right) \\ B &=\frac{9.2 \times 10^{-4} \mathrm{~V}}{(0.90 \mathrm{~m})\left(\sqrt{2\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)(32 \mathrm{~m})}\right)} \\ &=0.408 \times 10^{-4} \mathrm{~T}[/tex]
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