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Sagot :
Answer:
Width w = 4m
Glow depth = y1 = 20m
Outlet discharge = 40m
V1= velocity of flow = 40/20*4 = 1/2 = 0.5m/s
Froud number = v1/√gy1
= 0.5/√9.81x20 = 0.0356
1. Y2/20 = 1/2[-1+√1+8*(0.0356)²]
Y2 = 0.05
2. Energy loss in the jump = (20-0.05)²/4x20x0.05
= 1985m
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