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A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?

Sagot :

Answer: 50.7 J

Explanation:

Given

mass of lion is  [tex]m=2.6\ kg[/tex]

The initial speed of the lion is [tex]v_1=5\ m/s[/tex]

increased speed of lion is [tex]v_2=8\ m/s[/tex]

Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]

Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]

work did by lion after speed up is [tex]k_2-k_1[/tex]

[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]

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