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Sagot :

Answer:

[tex]6\sqrt2\\OR\\8.48528137[/tex]

Step-by-step explanation:

The area of a sector of a circle is found by:

[tex]A = \frac{\theta*r^2}{2}[/tex]

The question asks for the radius so the equation above can be repurposed

[tex]r = \sqrt\frac{2A}{\theta}[/tex]

A = 3pi

angle = pi/12

[tex]\frac{6\pi}{\pi/12} = \frac{72\pi}{\pi} = 72[/tex]

[tex]\sqrt{72} = 6\sqrt2 = 8.48528137[/tex]

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