Answered

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[tex]\sqrt(12-8x)=x-3[/tex]

Sagot :

Step-by-step explanation:

[tex]\sqrt{12-8x} =x-3\\[/tex]

square both sides

[tex]12-8x=(x-3)^2[/tex]

expand

[tex]12-8x=x^2-6x+9[/tex]

simplify

0=x^2+2x-3

Factor

0=(x+3)(x-1)

the possible values for x are -3 and 1

Hope that helps :)

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