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if y varies inversely as x, and y =35 when x =14, find x when y =15.

Sagot :

Leora03

Answer:

[tex]x = 32 \frac{2}{3} [/tex]

Step-by-step explanation:

[tex]y = \frac{k}{x} ,where \: k \: is \: a \: constant.[/tex]

Let's find the value of k first.

When y= 35, x= 14,

[tex]35 = \frac{k}{14} [/tex]

k= 14(35)

k= 490

Substitute the value of k into the equation:

[tex]y = \frac{490}{x} [/tex]

When y= 15,

[tex]15 = \frac{490}{x} [/tex]

15x= 490

x= 490 ÷15

[tex]x = 32 \frac{2}{3} [/tex]

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